Given that, $3{\rm{C}}\left( s \right) + 2{\rm{F}}{{\rm{e}}_2}{{\rm{O}}_3}\left( s \right) \to 4{\rm{Fe}}\left( s \right) + 3{\rm{C}}{{\rm{O}}_2}\left( {\rm{g}} \right)\Delta {H^o} = - 93657\,\,cal$ ${\rm{C}}\left( s \right) + {{\rm{O}}_2}\left( {\rm{g}} \right) \to {\rm{C}}{{\rm{O}}_2}\left( {\rm{g}} \right);\Delta {H^o} = - 94050$ cal If both the values of ∆H are at $25\,^\circ C$ then calculate $?H_{{\rm{F}}{{\rm{e}}_2}{{\rm{O}}_3}}^{\rm{o}}$

NEET UG CHEMISTRY MCQ: THERMODYNAMICS

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Application +4 | -1

Given that,

3\mathrm{C}\left( s \right) + 2\mathrm{F}{\mathrm{e}_2}{\mathrm{O}_3}\left( s \right) \to 4\mathrm{Fe}\left( s \right) + 3\mathrm{C}{\mathrm{O}_2}\left( \mathrm{g} \right)\Delta {H^o} = - 93657\,\,cal

\mathrm{C}\left( s \right) + {\mathrm{O}_2}\left( \mathrm{g} \right) \to \mathrm{C}{\mathrm{O}_2}\left( \mathrm{g} \right);\Delta {H^o} = - 94050

cal
If both the values of ∆H are at

25\,^\circ C

then calculate

?H_{\mathrm{F}{\mathrm{e}_2}{\mathrm{O}_3}}^\mathrm{o}

View answer and explanation

Correct option: C

- 94.25\,\,\mathrm{kcal}

Option C (-94.25 kcal) is the correct answer. It is calculated using Hess's Law by manipulating the given thermochemical equations to solve for the enthalpy of formation of Fe2O3.

NEET UG CHEMISTRY MCQ: THERMODYNAMICS

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