JEE MATHEMATICS MCQ: 2D GEOMETRY SYSTEM

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Analyzing +4 | -1

a, b, c

and

d

are the sides of a quadrilateral, then the minimum value of

\frac{a^2+b^2+c^2}{d^2}

View answer and explanation

Correct option: C

\frac{1}{3}

Option C (

\frac{{1}}{{3}}

) is correct because the minimum value of the expression is found by relating the sum of squares to the square of the sum, and using the triangle inequality.

More Questions from 2D GEOMETRY SYSTEM

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Values of

\alpha

(\alpha, 2 \alpha)

lies inside the

\Delta A B C

A(0,2), B(2,0)

and

C(4,4)

The locus of the moving point

P

, such that

2 P A=3 P B

where

A

(0,0)

and

B

(4,-3)

, is The incentre of the triangle with vertices

(1, \sqrt{3}),(0,0)

and

(2,0)

is The triangle with vertex

(1,5),(-3,1) \,\&\,(-2,1)

is The area of the quadrilateral with its vertices at the foci of the conics

9 x^2-16 y^2-18 x+32 y-23

=0

and

25 x^2+9 y^2-50 x-18 y+33=0

, is Orthocentre of the triangle whose vertices are

(0,0)(3,0)

and

(0,4)