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JEE PHYSICS MCQ: SEMI CONDUCTOR DEVICES

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The energy gap of silicon is 1.14 eV. The maximum wavelength at which silicon starts energy absorption, will be(h=6.62×10−34  Js;c=3×108ms−1h = 6.62 \times {10^{ - 34}}\mathrm{\;Js};\mathrm{c} = 3 \times {10^8}\mathrm{m}{\mathrm{s}^{ - 1}})
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Correct option: D
10888  A∘10888\;\mathop A\limits^ \circ
Option D (10888  A∘10888\;\mathop A\limits^ \circ) is correct because it is calculated using the formula λ=hcE\lambda = \frac{{hc}}{E} with the given energy gap.

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