JEE CHEMISTRY MCQ: SOLID STATE

1 Hard

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Application +4 | -1

CsBr

has BCC type structure with edge length 4.3 pm. The shortest inter ionic distance in between

C{s^ + }\,\& \,B{r^ - }

View answer and explanation

Correct option: A

3.72 pm

Option A (3.72 pm) is correct because it is calculated using the formula for the shortest interionic distance in a BCC structure, which is

\frac{{\sqrt{3}a}}{{2}}

, where a is the edge length.

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