JEE PHYSICS MCQ: OSCILLATIONS

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Application +4 | -1

A block of mass

1 \mathrm{~kg}

is fastened to a spring of spring constant of

100 \mathrm{~Nm}^{-1}

. The block is pulled to a distance

x=10 \mathrm{~cm}

from its equilibrium position

(x=0 \mathrm{~cm})

on a frictionless surface from rest

t=0

. The kinetic energy and the potential energy of the block when it is

5 \mathrm{~cm}

away from the mean position is

View answer and explanation

Correct option: A

0.375 \mathrm{~J},\,\,0.125 \mathrm{~J}

Option A (0.375 J, 0.125 J) is correct because the kinetic energy and potential energy are calculated using the formulas for SHM at the given displacement.

More Questions from OSCILLATIONS

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Assertion: A particle executing simple harmonic motion comes to rest at the extreme positions.

Reason: The resultant force on the particle is zero at these positions. A particle is subjected simultaneously to two SHM’s one along the

x

-axis and the other along the

y

-axis. The two vibrations are in phase and have unequal amplitudes. The particle will execute A particle is executing SHM with amplitude

a

. When the PE of a particle is one-fourth of its maximum value during the oscillation, its displacement from the equilibrium position will be The displacement, velocity and acceleration in a simple harmonic motion are related as the Assertion: Angular velocity of earth around sun is lesser than the angular velocity of moon about earth.
Reason: Time taken by moon revolve around earth is less than time taken by earth to revolve around sun. A particle is executing

SHM

. At a displacement

{y_1}

its potential energy is

{U_1}

and at a displacement

{y_2}

its potential energy is

{U_2}

. The potential energy of the particle at displacement

\left( {{y_1} + {y_2}} \right)