JEE PHYSICS MCQ: THERMODYNAMICS

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Application +4 | -1

The

\Delta H_f^{\circ}

for

\mathrm{CO}_2(\mathrm{~g}), \mathrm{CO}(\mathrm{g})

and

\mathrm{H}_2 \mathrm{O}(\mathrm{g})

are

-393.5,-110.5

and

-241.8 \mathrm{~kJ} \mathrm{~mol}^{-1}

respectively. The standard enthalpy change (in

\mathrm{kJ}

) for the reaction,

\mathrm{CO}_2(\mathrm{~g})+\mathrm{H}_2(\mathrm{~g}) \longrightarrow \mathrm{CO}(\mathrm{g})+\mathrm{H}_2 \mathrm{O}(\mathrm{g})

View answer and explanation

Correct option: B

41.2

Option B (25 mm) is correct because the separation is calculated by determining the positions of the proton and alpha particle when their velocities are perpendicular, considering their circular paths in the magnetic field.

JEE PHYSICS MCQ: THERMODYNAMICS

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