JEE PHYSICS MCQ: THERMODYNAMICS

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Application +4 | -1

An engine takes in compressed steam at

{127^ \circ }C

and rejects it at

{47^ \circ }C

. Efficiency of the engine is

View answer and explanation

Correct option: C

0.2

Option C (20%) is correct because the efficiency is calculated by using the formula

\eta = 1 - \frac{{{T_2}}}{{{T_1}}}

with temperatures in Kelvin.

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\left( {\gamma = \frac{{{C_p}}}{{{C_v}}}} \right)