NEET UG CHEMISTRY MCQ: ELECTRO CHEMISTRY

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{E^\mathrm{o}}

for the half cell,

Z{n^{2 + }}/Zn

- 0.76

, then emf of the cell

Zn/Z{n^{2 + }}\left( {1M} \right)//2{H^ + }\left( {1M} \right)/{H_2}\left( {1\,\,\mathrm{atm}} \right)

View answer and explanation

Correct option: B

+ \,0.76\,V

Option B (+ 0.76 V) is correct because the cell potential is calculated by reversing the sign of the zinc half-cell potential since it's being oxidized.

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