Let $f\left( x \right) = \frac{{\sqrt {\sin x} }}{{1 + \sqrt[3]{{\sin x}}}}.$ If $D$ is the domain of f, then $D$ contains

$\left( { - 2\;\pi , - \pi } \right)$

$\left( {3\;\pi ,4\;\pi } \right)$

$\left( {4\;\pi ,6\;\pi } \right)$

JEE MATHEMATICS MCQ: FUNCTIONS

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Understanding +4 | -1

Let

f\left( x \right) = \frac{{\sqrt {\sin x} }}{{1 + \sqrt[3]{{\sin x}}}}.

D

is the domain of f, then

D

contains

View answer and explanation

Correct option: A

\left( {0,\;\pi } \right)

Option A (

\left( {0,\;\pi } \right)

) is correct because

\sin x \ge 0

in the interval

\left( {0,\;\pi } \right)