JEE CHEMISTRY MCQ: P-BLOCK ELEMENTS

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Application +4 | -1

Sulphur reacts with chlorine in 1:2 ratio and forms

{X}

. Hydrolysis of

{X}

gives a sluphur compound

{Y}

. The hybridization of central atom in the anion

{Y}

View answer and explanation

Correct option: A

s p^3

Option A (

s p^3

) is correct because the sulphur compound formed after hydrolysis is

{H_2}S{O_3}

, and the hybridization of S in

{SO_3}^{2-}

sp^3

More Questions from P-BLOCK ELEMENTS

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17^{\text {th }}

{O}_2

{O}_2

\mathrm{C}{\mathrm{N}^ - }

{\mathrm{N}_2}

\mathrm{C}{\mathrm{N}^ - },\mathrm{\;}{\mathrm{N}_2}

2 {Fe}^{3+}+{SO}_2+2 {H}_2 {O} \rightarrow 2 {Fe}^{2+}+{SO}_4^{2-}+4 {H}^{+}

{H}_2 {~S}_2 {O}_8

{S}={O}

{S}-{OH}

{O}-

{O}

{NH}_3

{H}_2 {SO}_4

{H}_2 {SO}_4