JEE MATHEMATICS MCQ: FUNCTIONS

1 Hard

1 of 1

Application +4 | -1

[x]

be the greatest integer less than or equal to

x,

then

\sum\limits_{n = 8}^{100} {\left[ {\frac{{{{( - 1)}^n}n}}{2}} \right]}

is equal to

View answer and explanation

Correct option: B

Option B (4) is correct because the sum telescopes, leaving only the first few terms after cancellations.

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