In a Carnot engine, when ${T_2} = 0\,^\circ C\,\,\,{\rm{and}}\;\,\,{T_1} = 200\,^\circ C$ its efficiency is ${{\rm{\eta }}_1}{\rm{\;}}\,\,{\rm{and\;}}\,\,\,{\rm{when}}\;\,\,\,{T_1} = 0\,^\circ C\;\,\,{\rm{and}}\,\,\;{T_2} = - 200\,^\circ C\;,$ its efficiency is ${{\rm{\eta }}_2}$, then what in ${\eta _1}/{\eta _2}?$

JEE PHYSICS MCQ: THERMODYNAMICS

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In a Carnot engine, when 

{T_2} = 0\,^\circ C\,\,\,\mathrm{and}\;\,\,{T_1} = 200\,^\circ C

 its efficiency is  

{\mathrm{\eta }_1}\mathrm{\;}\,\,\mathrm{and\;}\,\,\,\mathrm{when}\;\,\,\,{T_1} = 0\,^\circ C\;\,\,\mathrm{and}\,\,\;{T_2} = - 200\,^\circ C\;,

 its efficiency is 

{\mathrm{\eta }_2}

, then what in 

{\eta _1}/{\eta _2}?

View answer and explanation

Correct option: A

0.577

Option A (0.577) is correct because it represents the ratio of the efficiencies calculated using the Carnot engine efficiency formula with the given temperatures converted to Kelvin.

JEE PHYSICS MCQ: THERMODYNAMICS

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