${E^ \circ }$ for ${\rm{F}}{{\rm{e}}^{2 + }} + 2{{\rm{e}}^ - } \to {\rm{Fe}}$ is -0.44 V and ${E^ \circ }$ for ${\rm{Z}}{{\rm{n}}^{2 + }} + 2{{\rm{e}}^ - } \to {\rm{Zn}}$ is -0.76 V thus

Zn is more electronegative than Fe

Fe is more electropositive than Zn

NEET UG CHEMISTRY MCQ: ELECTRO CHEMISTRY

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1 of 1

Understanding +4 | -1

{E^ \circ }

for

\mathrm{F}{\mathrm{e}^{2 + }} + 2{\mathrm{e}^ - } \to \mathrm{Fe}

is -0.44 V and

{E^ \circ }

for

\mathrm{Z}{\mathrm{n}^{2 + }} + 2{\mathrm{e}^ - } \to \mathrm{Zn}

is -0.76 V thus

View answer and explanation

Correct option: A

Zn is more electropositive than Fe

Option A (Zn is more electropositive than Fe) is correct because a more negative standard reduction potential indicates a greater tendency to be oxidized, meaning it is more electropositive.

More Questions from ELECTRO CHEMISTRY

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ions in solution by the same quantity of charge will be : The correct order of molar conductivity at infinite dilution of

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is When an aqueous solution of lithium chloride is electrolysed using graphite electrodes : Which are used as secondary reference electrodes?