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JEE MATHEMATICS MCQ: CIRCLES

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Application +4 | -1
The equation of family of circles with centre at (h,k)\left( {h,k} \right) touching the x−axisx - axis is given by
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Correct option: B
x2+y2−2hx−2ky+h2=0{x^2} + {y^2} - 2hx - 2ky + {h^2} = 0
The correct answer is B (x2+y2−2hx−2ky+h2=0{x^2} + {y^2} - 2hx - 2ky + {h^2} = 0) because it represents the equation of a circle with center (h, k) touching the x-axis.

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