JEE CHEMISTRY MCQ: CHEMICAL BONDING & MOLECULAR STRUCTURE

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Application +4 | -1

Which is expected to show paramagnetism?

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Correct option: A

\mathrm{Cl}{\mathrm{O}_2}

Option A (

\mathrm{Cl}{\mathrm{O}_2}

) is correct because it has an odd number of electrons (33), resulting in at least one unpaired electron and thus paramagnetism.

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\mathrm{C}{\mathrm{O}_2}

\left( A \right)\mathrm{HgC}{\mathrm{l}_2},\left( B \right)\mathrm{N}{\mathrm{O}_2},\left( C \right)\mathrm{SnC}{\mathrm{l}_4},\left( D \right){\mathrm{C}_2}{\mathrm{H}_2}

{BF}_3

{BCl}_3

{BF}_3

{BCl}_3

{B}-X \pi