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NEET UG CHEMISTRY MCQ: THERMODYNAMICS

1 Hard
1 of 1
Application +4 | -1
Consider the following cases of standard enthalpy of reaction (ΔHr∘\left(\Delta \mathrm{H}_{\mathrm{r}}^{\circ}\right. in kJ mol−1)\left.\mathrm{kJ} \mathrm{~mol}^{-1}\right)

C2H6(g)+72O2(g)→2CO2(g)+3H2O(ℓ);ΔH1∘=−1550C(graphite)+O2(g)→CO2(g);ΔH2∘=−393.5H2(g)+12O2(g)→H2O(ℓ);ΔH3∘=−286\begin{aligned} & \mathrm{C}_2 \mathrm{H}_6(\mathrm{g})+\frac{7}{2} \mathrm{O}_2(\mathrm{g}) \rightarrow 2 \mathrm{CO}_2(\mathrm{g})+3 \mathrm{H}_2 \mathrm{O}(\ell) ;\Delta \mathrm{H}_1^{\circ}=-1550 \\ & \mathrm{C}(\text {graphite})+\mathrm{O}_2(\mathrm{g}) \rightarrow \mathrm{CO}_2(\mathrm{g}) ;\Delta \mathrm{H}_2^{\circ}=-393.5 \\ & \mathrm{H}_2(\mathrm{g})+\frac{1}{2} \mathrm{O}_2(\mathrm{g}) \rightarrow \mathrm{H}_2 \mathrm{O}(\ell) ;\Delta \mathrm{H}_3^{\circ}=-286 \end{aligned}

The magnitude of ΔHf C2H6(g)∘\Delta \mathrm{H}_{\text{f }\mathrm{C}_2 \mathrm{H}_6(\mathrm{g})}^{\circ} is ____ kJ mol−1\mathrm{kJ} \mathrm{~mol}^{-1} (Nearest integer).
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Correct option: A
95
The correct answer is 95 because it involves using Hess's Law to calculate the enthalpy of formation of C2H6 from the given combustion and formation enthalpies.

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