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JEE MATHEMATICS MCQ: RELATIONS

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Application +4 | -1
Let R{R} be the relation on the set N{N} of natural numbers defined by
R:{(x,y)}:x+3y=12x∈N,y∈N}{R}:\{({x}, {y})\}: {x}+3 {y}=12 {x} \in {N}, {y} \in {N}\} then domain of R{R}
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Correct option: C
{9,6,3}\{9,6,3\}
Option C (9,6,3\\{9,6,3\\}) is correct because substituting y=1,2,3y = 1, 2, 3 into the equation x+3y=12x + 3y = 12 yields x=9,6,3x = 9, 6, 3 respectively, and these are the only natural number solutions.

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