Back to SYSTEM OF PARTICLES

JEE PHYSICS MCQ: SYSTEM OF PARTICLES

1 Medium

1 of 1

Application +4 | -1

A particle is under uniform circular motion with angular momentum L. If its kinetic energy is tripled and frequency of motion is halved then new angular momentum becomes

View answer and explanation

Correct option: D

6 L

Option D (6 L) is correct because the new angular momentum is 6 times the original angular momentum, derived from the relationship between kinetic energy, angular momentum, and frequency.

More Questions from SYSTEM OF PARTICLES

Practice All Chapter MCQs →

It is easier for a swimmer jumping into water from a height to describe a loop in the air by A uniform thin rod

\mathrm{AB}

\mathrm{L}

has linear mass density

\mu(x)=a+\frac{b x}{L}

x

is measured from

\mathrm{A}

\mathrm{CM}

of the rod lies at a distance of

\left(\frac{7}{12}\right) \mathrm{L}

\mathrm{A}

\mathrm{b}

are related as : A solid metal ring and a disc of same radius and mass are rotating about their diameters with same angular frequency. The ratio of their respective rotational kinetic energy values is When a torque acting upon a system is zero, then which of the following will be constant A point particle of mass

1.0 \mathrm{~g}

is rotating in a circle of diameter

8 \mathrm{~cm}

. Its moment of inertia will be The angular velocity of a particle is given by

\omega = {t^4} + 2{t^3}

then its angular acceleration of the particle at

t = 1\,sec

\left( {rad\,{s^{ - 2}}} \right)