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JEE MATHEMATICS MCQ: COMPLEX NUMBERS

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If z{z} satisfies the equation (z−2z+2)(zˉ−2zˉ+2)=1\left(\frac{z-2}{z+2}\right)\left(\frac{\bar{z}-2}{\bar{z}+2}\right)=1, then minimum value of ∣z∣|z| is equal to:
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Correct option: A
0
The correct answer is A (0) because the given equation simplifies to |z-2| = |z+2|, which represents the perpendicular bisector of the line joining 2 and -2, i.e., the y-axis. The minimum value of |z| is 0, occurring at the origin.

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