The value of g on the earth’s surface is $980{\rm{\;cm}}{{\rm{s}}^{ - 2}}$. Its value at a height of 64 km from the earth’s surface is

$960.40{\rm{\;cm}}{{\rm{s}}^{ - 2}}$

$984.90{\rm{\;cm}}{{\rm{s}}^{ - 2}}$

$982.45{\rm{\;cm}}{{\rm{s}}^{ - 2}}$

$977.55{\rm{\;cm}}{{\rm{s}}^{ - 2}}$

JEE PHYSICS MCQ: GRAVITATION

1 Medium

1 of 1

Application +4 | -1

The value of g on the earth’s surface is

980\mathrm{\;cm}{\mathrm{s}^{ - 2}}

. Its value at a height of 64 km from the earth’s surface is

View answer and explanation

Correct option: A

960.40\mathrm{\;cm}{\mathrm{s}^{ - 2}}

Option A (

960.40\\;\mathrm{cm}{\mathrm{s}^{ - 2}}

) is correct because it is calculated using the formula for the variation of g with height.

Practice All Chapter MCQs →

11.2\mathrm{\;\;km}{\mathrm{s}^{ - 1}}

{45^0}

v_e

\theta