The function $f(x)=\log \left(x+\sqrt{x^2+1}\right)$ is

Neither an even nor an odd function

JEE MATHEMATICS MCQ: FUNCTIONS

1 Easy

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Understanding +4 | -1

The function

f(x)=\log \left(x+\sqrt{x^2+1}\right)

View answer and explanation

Correct option: C

An odd function

Option C (An odd function) is correct because f(-x) = -f(x) for all x in the domain, which is the definition of an odd function.

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