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JEE MATHEMATICS MCQ: COMPLEX NUMBERS

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Analyzing +4 | -1
If at least one value of the complex number z=x+i  yz = x + i\;y satisfy the condition ∣z+2∣=a2−3a+2\left| {z + \sqrt 2 } \right| = \sqrt {{a^2} - 3a + 2} and the inequality ∣z+i2∣<a,\left| {z + i\sqrt 2 } \right| < a, then
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Correct option: A
a>2a > 2
Option A is correct. The condition for the intersection of the two circles leads to the inequality a>2a > 2.

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