JEE MATHEMATICS MCQ: FUNCTIONS

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Analyzing +4 | -1

f(x)=x^2+2 b x+2 c^2

and

g(x)=-x^2-2 c x+b^2

are such that

\min f(x)>\max g(x)

, then relation between

{b}

and

{c}

, is:

View answer and explanation

Correct option: D

|c| > \sqrt{2}|b|

The correct answer is

|c| > \sqrt{2}|b|

because the condition

\min f(x) > \max g(x)

leads to the inequality

c^2 > 2b^2

, which simplifies to the given relation.

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