Skip to main content
Back to TRIGONOMETRY RATIOS

JEE MATHEMATICS MCQ: TRIGONOMETRY RATIOS

1 Easy
1 of 1
Application +4 | -1
If acos⁡3α+3a  cos⁡α  sin⁡2=m  a{\cos ^3}\alpha + 3a\,\,\cos \alpha \,\,{\sin ^2} = m\; and a  sin⁡3α+3a  cos⁡2α  sin⁡α=n,   then  (m+n)2/3+  (m−n)2/3  a\,\,{\sin ^3}\alpha + 3a\,\,{\cos ^2}\alpha \,\,\sin \alpha = n,\;\,\mathrm{then}\;{\left( {m + n} \right)^{2/3}} + \;{\left( {m - n} \right)^{2/3}}\; is equal to
View answer and explanation
Correct option: C
2a2/32{a^{2/3}}
Option C (2a2/32{a^{2/3}}) is correct because simplifying the given expressions and using the binomial theorem leads to 2a2/32{a^{2/3}}.

More Questions from TRIGONOMETRY RATIOS

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.