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NEET UG CHEMISTRY MCQ: 13 TH GROUP ELEMENTS (P-BLOCK)

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B{F_3}

on hydrolysis forms

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Correct option: C

Both (1) and (2)

Option C (Both (1) and (2)) is correct because

BF_3

on hydrolysis forms both boric acid (

H_3BO_3

) and tetrafluoroboric acid (

HBF_4

).

More Questions from 13 TH GROUP ELEMENTS (P-BLOCK)

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The hardest compound of boron is: Which does not show inert pair effect? Which one of the following does not exist in the free state On strong heating of

{H}_3 {PO}_4

{H}_3 {BO}_3

, sum of oxidation number of

{P}\, \& {~B}

in the final product obtained is Compound ‘X’ reacts with

N{H_3}

to 473 K give another compound ‘Y’. X can be prepared by heating

B{F_3}

with sodium hydride. The compound ‘Y’ is represented by the formula Assertion: Electronegativity first increases from B to Al and then decreases from Al to

\mathrm{TI}

.

Reason: Due to poor shielding by inner

\mathrm{d}

\mathrm{f}