For a chemical reaction $2X + Y \to Z$, the rate of appearance of $Z\;is\;0.05\;{\rm{mol}}\;{{\rm{L}}^{ - 1}}{\rm{.}}$ The rate of disappearance of $X$ will be

$0.1\;{\rm{mol}}\;{{\rm{L}}^{ - 1}}\;{\min ^{ - 1}}$

$0.05\;{\rm{mol}}\;{{\rm{L}}^{ - 1}}\;{{\rm{h}}^{ - 1}}$

$0.05\;{\rm{mol}}\;{{\rm{L}}^{ - 1}}\;{\min ^{ - 1}}$

$0.25\;{\rm{mol}}\;{{\rm{L}}^{ - 1}}\;{\min ^{ - 1}}$

NEET UG CHEMISTRY MCQ: CHEMICAL KINETICS

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Application +4 | -1

For a chemical reaction

2X + Y \to Z

, the rate of appearance of

Z\;is\;0.05\;\mathrm{mol}\;{\mathrm{L}^{ - 1}}\mathrm{.}

The rate of disappearance of

X

will be

View answer and explanation

Correct option: C

0.1\;\mathrm{mol}\;{\mathrm{L}^{ - 1}}\;{\min ^{ - 1}}

Option C (

0.1\;\mathrm{mol}\;{\mathrm{L}^{ - 1}}\;{\min ^{ - 1}}

) is correct because the rate of disappearance of X is twice the rate of appearance of Z, based on the stoichiometry of the reaction.