JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

1 Easy

1 of 1

Application +4 | -1

I=\int \frac{\log \left(x+\sqrt{1+x^2}\right)}{\sqrt{1+x^2}} d x

, then I equals

View answer and explanation

Correct option: B

(1 / 2)\left(\log \left(x+\sqrt{1+x^2}\right)\right)^2+C

Option B (\

1/2)(\log(x + \sqrt{1+x^2}))^2 + C

is correct. The integral is solved by using the substitution \

t = \log(x + \sqrt{1+x^2}))

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