JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Analyzing +4 | -1

Observe that

1^3=1,2^3=3+5

3^3=7+9+11,4^3=13+15+17+19

. Then,

n^3

as a similar series is

View answer and explanation

Correct option: C

\left(n^2-n+1\right)+\left(n^2-n+3\right)+\left(n^2-n+5\right)

+\ldots+\left(n^2+n-1\right)

Option C (

\left(n^2-n+1\right)+\left(n^2-n+3\right)+\left(n^2-n+5\right) +\ldots+\left(n^2+n-1\right)

) is correct because it represents the sum of n consecutive odd numbers starting from

n^2 - n + 1

, which equals

n^3

More Questions from SEQUENCE OF SERIES

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\log \left(\frac{a}{3 b}\right)

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\frac{3}{4}