JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Analyzing +4 | -1

a=\log _{12} 18

and

b=\log _{24} 54

, then the value of

(a+b)^2+a(10-a)-b(10+b)

is equal to

View answer and explanation

Correct option: C

The correct answer is C (2). The expression simplifies to

a^2 + b^2 + 2ab + 10a - a^2 - 10b - b^2 = 2

after substituting the given values of

a

and

b

and simplifying the logarithmic expressions.

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