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JEE MATHEMATICS MCQ: PROPERTIES OF TRIANGLES

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In a △ABC,A:B:C=3:5:4\triangle \mathrm{ABC}, \mathrm{A}: \mathrm{B}: \mathrm{C}=3: 5: 4.Then a+b+c2\mathrm{a}+\mathrm{b}+\mathrm{c} \sqrt{2} is equal to
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Correct option: C
3 b3 \mathrm{~b}
Option C (3 b3 \mathrm{~b}) is correct because after substituting the values of a, b, and c in terms of b, the expression simplifies to 3b.

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