For the reaction equilibrium, $2{\rm{NOBr}}\left( {\rm{g}} \right)\;\leftrightharpoons\;2{\rm{NO}}\left( {\rm{g}} \right) + {\rm{B}}{{\rm{r}}_2}\left( {\rm{g}} \right),$ if ${P_{{\rm{B}}{{\rm{r}}_2}}} = \frac{P}{9}$ at equilibrium and $P$ is total pressure. The ratio ${K_p}/P$ is equal to:

NEET UG CHEMISTRY MCQ: Equilibrium

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For the reaction equilibrium,

2\mathrm{NOBr}\left( \mathrm{g} \right)\;\leftrightharpoons\;2\mathrm{NO}\left( \mathrm{g} \right) + \mathrm{B}{\mathrm{r}_2}\left( \mathrm{g} \right),

{P_{\mathrm{B}{\mathrm{r}_2}}} = \frac{P}{9}

at equilibrium and

P

is total pressure. The ratio

{K_p}/P

is equal to:

View answer and explanation

Correct option: B

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Option B is correct because the Kp/P ratio can be calculated from the given partial pressure of Br2 and the stoichiometry of the reaction.

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Mg{(HC{O_3})_2}

MgC{O_3}

Mg{(OH)_2}

MgC{O_3}

K_{\mathrm{P}}

\mathrm{CaCO}_3

4.5 \times 10^{-2}

\mathrm{C}(\mathrm{s})+\mathrm{CO}_2(\mathrm{g}) \rightleftharpoons 2 \mathrm{CO}(\mathrm{g}),

K_{\mathrm{P}}

2.0 \mathrm{~atm}.

\mathrm{CaO}

\mathrm{CaCO}_3

+

\leftrightharpoons

\mathrm{PC}{\mathrm{l}_5}\leftrightharpoons\mathrm{PC}{\mathrm{l}_3} + \mathrm{C}{\mathrm{l}_2}

{K_{\mathrm{eq}}} = 0.41

\mathrm{p}{K_a}