JEE PHYSICS MCQ: THERMAL PROPERTIES OF MATTER

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Application +4 | -1

A slab consists of two parallel layers of two different materials of same thickness having thermal conductivities

{{K_1}}

and

{{K_2}}

. The equivalent conductivity of the combination is

View answer and explanation

Correct option: B

{\frac{{{K_1} + {K_2}}}{2}}

Option B (

{\frac{{{K_1} + {K_2}}}{2}}

) is correct because it represents the equivalent thermal conductivity for two layers in parallel with equal thickness.

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