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JEE MATHEMATICS MCQ: COMPLEX NUMBERS

1 Easy
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Application +4 | -1
If a+ib=∑k=1101ika+i b=\sum\limits_{{k=1}}^{101} i^k, then (a,b)(a, b) equals
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Correct option: A
(0,1)(0,1)
Option A ((0,1)(0,1)) is correct because the sum of the series ∑k=1101ik\sum_{k=1}^{101} i^k simplifies to ii, which corresponds to the complex number 0+1i0 + 1i.

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