JEE MATHEMATICS MCQ: TRIGONOMETRY RATIOS

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Application +4 | -1

The sides of a

\triangle A B C

are in AP, if the angles

A

and

C

are the greatest and the smallest angles respectively, then

4(1-\cos A)(1-\cos C)

is equal to

View answer and explanation

Correct option: B

4 \cos ^2 \frac{A+C}{2}

Option B (

4 \cos ^2 \frac{{A+C}}{{2}}

) is correct because by using the properties of AP and trigonometric identities, the expression simplifies to this form.

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\tan \alpha=\frac{p}{q}

\alpha=6 \beta

\alpha

\frac{1}{2}[p \operatorname{cosec} 2 \beta-q \sec 2 \beta]

\cos 12^{\circ}+\cos 84^{\circ}+\cos 156^{\circ}+\cos 132^{\circ}

\triangle A B C

C

{\sin ^6}\,\,\theta + {\cos ^6}\,\,\theta + 3{\sin ^2}\,\,\theta \,\,{\cos ^2}\,\,\theta

\sin ^2 \frac{A}{2}+\sin ^2 \frac{B}{2}+\sin ^2 \frac{C}{2}=

\sin ^2(A / 2)+\sin ^2(B / 2)-\sin ^2(C / 2)=