If $I=\int \frac{\sin 2 x}{(3+4 \cos x)^3} d x$, then $I=$

$\frac{3 \cos x+8}{(3+4 \cos x)^2}+C$

$\frac{3+\cos x}{(3+4 \cos x)^2}+C$

JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

1 Easy

1 of 1

Application +4 | -1

I=\int \frac{\sin 2 x}{(3+4 \cos x)^3} d x

, then

I=

View answer and explanation

Correct option: B

\frac{3+8 \cos x}{16(3+4 \cos x)^2}+C

Option B is correct. The integral is solved using substitution, where

t = 3 + 4\cos x

, simplifying the expression and allowing for direct integration.

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