Let $f(x)=\frac{x-3}{x+1}, x \neq-1$. Then $f^{2010}$ (2014) (where $f^n(x)=f o f \ldots$ of $(x)(n$ times)) is

JEE MATHEMATICS MCQ: FUNCTIONS

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Analyzing +4 | -1

Let

f(x)=\frac{x-3}{x+1}, x \neq-1

. Then

f^{2010}

(2014) (where

f^n(x)=f o f \ldots

(x)(n

times)) is

View answer and explanation

Correct option: D

2014

Option D (2014) is correct because the function repeats every 3 iterations, and 2010 is a multiple of 3, so f²⁰¹⁰(2014) = 2014.

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