What is the molality of ethyl alcohol (mol. wt. = 416) in aqueous solution which freezes at $ - 10^\circ {\rm{C}}?.\;\left( {{K_f}\;{\rm{for}}\;{\rm{ water}} = 1.86\;{\rm{K}}\;{\rm{ molalit}}{{\rm{y}}^{ - 1}}} \right)$

NEET UG CHEMISTRY MCQ: SOLUTIONS

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Application +4 | -1

What is the molality of ethyl alcohol (mol. wt. = 416) in aqueous solution which freezes at

- 10^\circ \mathrm{C}?.\;\left( {{K_f}\;\mathrm{for}\;\mathrm{ water} = 1.86\;\mathrm{K}\;\mathrm{ molalit}{\mathrm{y}^{ - 1}}} \right)

View answer and explanation

Correct option: C

5.376

Option C is correct because the molality is calculated using the formula

\Delta T_f = K_f \times m

, where

\Delta T_f

is the freezing point depression,

K_f

is the cryoscopic constant, and m is the molality.

Practice All Chapter MCQs →

0.52\,K\,kg\,mo{l^{ - 1}}

A

B

B

A

B

--{0.93^0}C

{K_f}

1.86\mathrm{ }K\mathrm{ }kg\mathrm{ }mo{l^{ - 1}}