If $\sec \,\,\theta + \tan \,\,\theta = k,\,\,\cos \,\,\theta $ equals to

JEE MATHEMATICS MCQ: TRIGONOMETRY RATIOS

1 Easy

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Application +4 | -1

\sec \,\,\theta + \tan \,\,\theta = k,\,\,\cos \,\,\theta

equals to

View answer and explanation

Correct option: B

\frac{{2k}}{{{k^2} + 1}}

Option C (

\frac{8}{15}

) is correct because by using the area formula and Heron's formula, we can find the value of tan B.

Practice All Chapter MCQs →

\tan \alpha=\frac{p}{q}

\alpha=6 \beta

\alpha

\frac{1}{2}[p \operatorname{cosec} 2 \beta-q \sec 2 \beta]

\cos 12^{\circ}+\cos 84^{\circ}+\cos 156^{\circ}+\cos 132^{\circ}

\triangle A B C

C

{\sin ^6}\,\,\theta + {\cos ^6}\,\,\theta + 3{\sin ^2}\,\,\theta \,\,{\cos ^2}\,\,\theta

\sin ^2 \frac{A}{2}+\sin ^2 \frac{B}{2}+\sin ^2 \frac{C}{2}=

\sin ^2(A / 2)+\sin ^2(B / 2)-\sin ^2(C / 2)=