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JEE PHYSICS MCQ: KINETIC THEORY OF GASES

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Average K.E. of one single molecule of monoatomic gas is 0.414eV0.414 \mathrm{eV} (of ⊥\perp molecule). What will be is temp == ?
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Correct option: B
3200 K
Option B (3200 K) is correct because the temperature is calculated using the average kinetic energy formula for a monoatomic gas, KE=32kTKE = \frac{3}{2}kT.

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