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JEE PHYSICS MCQ: SYSTEM OF PARTICLES

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A uniform circular disc of mass 200 g200 \mathrm{~g} and radius 4.0 cm4.0 \mathrm{~cm} is rotated about one of its diameter at an angular speed of 20rad/s20 \mathrm{rad} / \mathrm{s}. Find its angular momentum ( in kg−m/s\mathrm{kg}-\mathrm{m} / \mathrm{s} ) about the axis of rotation.
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Correct option: A
16.0×10−516.0 \times 10^{-5}
Option A (16.0×10−516.0 \times 10^{-5}) is correct because it is calculated by finding the moment of inertia about the diameter and then multiplying by the angular speed.

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