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JEE PHYSICS MCQ: OSCILLATIONS

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The elongation of spring of length LL and of negligible mass due to a force is xx. the spring is cut into two pieces of length in ratio 1:n1: n. The ratio of the respective spring constants is:
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Correct option: A
n:1{n}: 1
Option A is correct because the spring constant is inversely proportional to the length of the spring, so when the spring is cut into a ratio of 1:n, the spring constants are in the ratio of n:1.

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