NEET UG CHEMISTRY MCQ: Equilibrium

1 Hard

1 of 1

Analyzing +4 | -1

{N}_2 {O}_4(\mathrm{g}) \rightleftharpoons 2 {NO}_2(\mathrm{g})

For the reaction, if the percentage dissociation of

{N}_2 {O}_4

are

25 \%, 50 \%, 75 \%

and

100 \%

, then the sequence of observed vapour densities will be

\left({d}_1, {~d}_2, {~d}_3\right.

and

{d}_4

are vapour density at

25 \%, 50 \%

75 \%

and

100 \%

dissociation respectively)

View answer and explanation

Correct option: A

d_1>d_2>d_3>d_4

Option A (

d_1>d_2>d_3>d_4

) is correct because as the percentage dissociation increases, the number of moles increases, leading to a decrease in vapor density.

More Questions from Equilibrium

Practice All Chapter MCQs →

Mg{(HC{O_3})_2}

MgC{O_3}

Mg{(OH)_2}

MgC{O_3}

K_{\mathrm{P}}

\mathrm{CaCO}_3

4.5 \times 10^{-2}

\mathrm{C}(\mathrm{s})+\mathrm{CO}_2(\mathrm{g}) \rightleftharpoons 2 \mathrm{CO}(\mathrm{g}),

K_{\mathrm{P}}

2.0 \mathrm{~atm}.

\mathrm{CaO}

\mathrm{CaCO}_3

+

\leftrightharpoons

\mathrm{PC}{\mathrm{l}_5}\leftrightharpoons\mathrm{PC}{\mathrm{l}_3} + \mathrm{C}{\mathrm{l}_2}

{K_{\mathrm{eq}}} = 0.41

\mathrm{p}{K_a}