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NEET UG CHEMISTRY MCQ: REDOX REACTIONS

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In alkaline condition KMnO4\mathrm{KMn}{\mathrm{O}_4} reacts as follows, 2KMnO4+2KOH→2K2MnO4+H2O+O\begin{array}{llllllllllllllllllll} {2\mathrm{KMn}{\mathrm{O}_4} + 2\mathrm{KOH} \to 2{\mathrm{K}_2}\mathrm{Mn}{\mathrm{O}_4} + {\mathrm{H}_2}\mathrm{O} + \mathrm{O}} \end{array} Therefore, its equivalent weight will be :
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Correct option: D
158
Option D (158) is correct because the equivalent weight is the molecular weight divided by the change in oxidation number, which is 1 in this case, but the reaction shows 2KMnO4 reacting.

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