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JEE PHYSICS MCQ: THERMODYNAMICS

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A carnot engine takes 3×106  cal3 \times {10^6}\,\,cal of heat from a reservoir at 6270C{627^0}C and gives it to a sink at 270C{27^0}C. The work done by the engine is,
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Correct option: B
8.4×106J8.4 \times {10^6}J
Option B (8.4×106J8.4 \times {10^6}J) is correct because it is calculated using the Carnot engine efficiency formula and the heat absorbed and rejected.

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