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JEE MATHEMATICS MCQ: FUNCTIONS

1 Easy
1 of 1
Application +4 | -1
The domain of the function f(x)=sin⁡−1[log⁡2(x/2)]f(x)=\sin ^{-1}\left[\log _{2}(x / 2)\right] is
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Correct option: A
[1,4][1,4]
Option A ([1,4]) is correct because the domain is found by solving the inequality -1 <= log2(x/2) <= 1.

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