Skip to main content
Back to THERMODYNAMICS

JEE PHYSICS MCQ: THERMODYNAMICS

1 Medium
1 of 1
Analyzing +4 | -1
Statement-I: Monoatomic, diatomic and polyatomic gases are adiabatically compressed such that compression ratio is (P2P1)\left(\frac{P_2}{P_1}\right). Then monoatomic gas will have maximum final volume out of these three gases.
Statement-II: Monoatomic gas has least degree of freedom.
View answer and explanation
Correct option: A
Statement-I is true and statement-II is true
Option A (Statement-I is true and statement-II is true) is correct because monoatomic gases have the least adiabatic index, leading to a maximum final volume after adiabatic compression, and they have the fewest degrees of freedom.

More Questions from THERMODYNAMICS

Practice All Chapter MCQs →
The work done in which of the following process is zero? Water is used to cool the radiators of engines in cars because A gas expand 0.25  m30.25\,\,{m^3} at constant pressure 103N/m2,{10^3}N/{m^2}, the work done is A thermodynamic process in which temperature TT of the system remains constant though other variable PP and VV may change, is called What is the slope for an isothermal process? For adiabatic processes (γ=CpCv)\left( {\gamma = \frac{{{C_p}}}{{{C_v}}}} \right)
Type at least 2 characters or jump directly:
🩺 NEET MCQs 🔬 JEE MCQs 🎯 JEE College Predictor Study guides 📊 Dashboard
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.

Continue with Free Account →