JEE MATHEMATICS MCQ: TRIGONOMETRY RATIOS

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Application +4 | -1

Sides of a

\triangle A B C

are in AP, if

a<

minimum

\{b, c\}

, then

\cos A

is equal to

View answer and explanation

Correct option: D

\frac{4 c-3 b}{2 c}

Option D (

\frac{4 c-3 b}{2 c}

) is correct because by considering the possible arithmetic progressions and applying the cosine rule, this expression for

\cos A

is obtained.

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C

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