Skip to main content
Back to Equilibrium

NEET UG CHEMISTRY MCQ: Equilibrium

1 Hard
1 of 1
Application +4 | -1
0.150.15 mole of pyridinium chloride has been added into 500 mL500 \mathrm{~mL} of 0.2 M0.2 \mathrm{~M} pyridine solution. Find the pH\mathrm{pH} and [OH−]\left[\mathrm{OH}^{-}\right] ion concentration in the resulting solution. Kb=1.5×10−9M\mathrm{K}_{\mathrm{b}}=1.5 \times 10^{-9} \mathrm{M} (assuming no change in volume).
View answer and explanation
Correct option: A
10−910^{-9}
Option C (10−1010^{-10}) is correct because it correctly calculates the hydroxide ion concentration in the buffer solution using the given Kb value and the concentrations of pyridine and pyridinium chloride.

More Questions from Equilibrium

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.