JEE MATHEMATICS MCQ: PROPERTIES OF TRIANGLES

1 Easy

1 of 1

Analyzing +4 | -1

In any

\triangle A B C

, the simplified form of

\frac{\cos 2 A}{a^2}-\frac{\cos 2 B}{b^2}

View answer and explanation

Correct option: C

\frac{1}{a^2}-\frac{1}{b^2}

Option C (

\frac{1}{a^2}-\frac{1}{b^2}

) is correct because the expression simplifies to this form using trigonometric identities and the sine rule.

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