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JEE MATHEMATICS MCQ: PAIR OF STRAIGHT LINES

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Application +4 | -1
If a,x1,x2a, x_1, x_2 are in G.P. with common ratio rr, and b,y1,y2b, y_1, y_2 are in G.P. with common ratio ss where s−r=2s-r=2, then the area of the triangle with vertices (a,b)(a, b), (x1,y1)\left(x_1, y_1\right) and (x2,y2)\left(x_2, y_2\right) is
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Correct option: A
∣ab(r2−1)∣\left|a b\left(r^2-1\right)\right|
Option C ((0,0)) is correct because the triangle formed by the lines is a right-angled triangle at the origin, and the orthocenter of a right-angled triangle is the vertex at the right angle.

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